A) equilateral
B) isosceles
C) scalene
D) none of these
Correct Answer: A
Solution :
[a] Let \[\alpha =\frac{\pi -A}{4},\beta =\frac{\pi -B}{4},\gamma =\frac{\pi -C}{4}\] \[\Rightarrow \,\alpha +\beta +\gamma =\frac{\pi }{2}\] \[\Rightarrow \,\sum{\tan \alpha \tan \beta =1}\] \[\Rightarrow \,\sum{{{\tan }^{2}}\alpha =1=\sum{\tan \alpha \tan }\beta }\] \[\Rightarrow \] \[\tan \alpha =\tan \beta =\tan \gamma \]
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