A) 2%
B) 4%
C) 7%
D) 10%
Correct Answer: C
Solution :
[c] Given that \[\frac{\Delta l}{l}\times\] 100=+1%and \[\frac{\Delta T}{T}\times\] 100=-3% Percentage error in the measurement of g is \[\left[ \frac{4{{\pi }^{2}}l}{{{T}^{2}}} \right]=100\times \frac{\Delta l}{l}-2\times \frac{\Delta T}{T}\times 100\] =1%-2[-3%]=+7%You need to login to perform this action.
You will be redirected in
3 sec