A) \[M_{0}^{{}}LT_{{}}^{2}\]
B) \[M_{{}}^{0}L_{{}}^{2}T_{{}}^{-4}\]
C) \[M_{{}}^{0}L_{{}}^{{}}T_{{}}^{-3}\]
D) \[M_{{}}^{0}L_{{}}^{2}T_{{}}^{-1}\]
Correct Answer: D
Solution :
[d] [n]= Number of particles crossing a unit area in unit time =\[[{{L}^{-2}}{{T}^{-1}}]\] \[[{{n}_{2}}]=[{{n}_{1}}]\]=number of particles per unit valume= \[[{{L}^{-3}}]\] \[[{{x}_{2}}]=[{{x}_{1}}]\]= positions \[\therefore \,\,D=\frac{[n][{{x}_{2}}-{{x}_{1}}]}{[{{n}_{2}}-{{n}_{1}}]}=\frac{[{{L}^{-2}}{{T}^{-1}}]\times [L]}{[{{L}^{-3}}]}=[{{L}^{2}}{{T}^{-1}}]\]You need to login to perform this action.
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