A) 500 Hz
B) 1000 Hz
C) 2000 Hz
D) 4000 Hz
Correct Answer: B
Solution :
[b] When the piston is moved through a distance of 8.75 cm, the path difference produced is \[2\times 8.75\] cm = 17.5 cm. This must be equal to\[\frac{\lambda }{2}\] for maximum to change to minimum. \[\therefore \frac{\lambda }{2}=17.5cm\Rightarrow \lambda =35cm=0.35cm\] So, \[v=n\lambda \Rightarrow n=\frac{v}{\lambda }=\frac{350}{0.35}=1000Hz\]You need to login to perform this action.
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