A) Square
B) Rhombus
C) Rectangle
D) Parallelogram
Correct Answer: D
Solution :
Given \[\mathbf{a}+\mathbf{c}=\mathbf{b}+\mathbf{d}\Rightarrow \frac{1}{2}(\mathbf{a}+\mathbf{c})=\frac{1}{2}(\mathbf{b}+\mathbf{d})\] Here, mid points of \[\overrightarrow{AC}\] and \[\overrightarrow{BD}\] coincide, where \[\overrightarrow{AC}\] and \[\overrightarrow{BD}\] are diagonals. In addition, we know that diagonals of a parallelogram bisect each other. Hence quadrilateral is parallelogram.You need to login to perform this action.
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