Answer:
Let ABCD be the square field, each side measuring a units. Let the tortoise start from B and reach, the diagonally opposite corner in a time interval of t.
\[Average\,\,velocity=\frac{Total\,\,displacement}{Total\,time}\]
From the figure, DB is the displacement of the tortoise,
\[DB=\sqrt{{{a}^{2}}+{{a}^{2}}}=\sqrt{2{{a}^{2}}}=\sqrt{2}a\]
Average velocity of the tortoise \[=\frac{\sqrt{2}a}{t}\]
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