Answer:
Given\[s\propto {{t}^{3}}\] or \[s=k{{t}^{3}}\] \[\therefore \]Velocity\[=\frac{ds}{dt}=3k{{t}^{2}}\] Acceleration \[=\frac{d\upsilon }{dt}=6kt\] i.e., acceleration\[\propto t\]. Clearly, the acceleration increases uniformly with time.
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