question_answer

A body of weight 2kg is suspended as shown in the figure. The tension \[{{T}_{1}}\] in the horizontal string (in kg wt) is [Kerala PMT 2002]          

A)             \[2/\sqrt{3}\]

B)               \[\sqrt{3}/2\]

C)             \[2\sqrt{3}\]    

D)             \[2\]

Correct Answer: C

Solution :

                \[T\sin 30=2kg\,wt\]             Þ \[T=4\,kg\,wt\]             \[{{T}_{1}}=T\cos 30\]°             \[=4\cos 30\]°             \[=2\sqrt{3}\]