A) 20 N
B) 40 N
C) 10 N
D) 32 N
Correct Answer: D
Solution :
\[{{T}_{2}}=({{m}_{1}}+{{m}_{2}})\times \frac{{{T}_{3}}}{{{m}_{1}}+{{m}_{2}}+{{m}_{3}}}=\frac{(10+6)\times 40}{20}\]\[=32\ N\]You need to login to perform this action.
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