A) \[19.6sin{{45}^{o}}\]
B) \[19.6\text{ }cos\text{ }{{45}^{o}}\]
C) \[9.8sin{{45}^{o}}\]
D) \[9.8\text{ }cos\text{ }{{45}^{o}}\]
Correct Answer: A
Solution :
For angle of repose, Friction =Component of weight along the plane =\[mg\sin \theta \]\[=2\times 9.8\times \sin {{45}^{o}}\]\[=19.6\sin {{45}^{o}}\]
You need to login to perform this action.
You will be redirected in
3 sec
