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JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Motion on Inclined Surface

  • question_answer
    A block of mass 1 kg slides down on a rough inclined plane of inclination \[{{60}^{o}}\] starting from its top. If the coefficient of kinetic friction is 0.5 and length of the plane is 1 m, then work done against friction is  (Take\[g=\text{ }9.8m/{{s}^{2}}\]) [AFMC 2000; KCET 2001]

    A)             9.82 J

    B)             4.94 J

    C)             2.45J  

    D)             1.96 J

    Correct Answer: C

    Solution :

                    \[W=\mu mg\cos \theta \,S=0.5\times 1\times 9.8\times \frac{1}{2}\times 1=2.45\ J\]


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