A) \[\sqrt{2gl(\mu \cos \theta -\sin \theta )}\]
B) \[\sqrt{2gl(\sin \theta -\mu \cos \theta )}\]
C) \[\sqrt{2gl(\sin \theta +\mu \cos \theta )}\]
D) \[\sqrt{2gl(\cos \theta +\mu \sin \theta )}\]
Correct Answer: B
Solution :
Acceleration \[=g(\sin \theta -\mu \ \cos \theta )\] and s = l \[v=\sqrt{2as}\]\[=\sqrt{2gl(\sin \theta -\mu \cos \theta )}\]
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