A) 5 : 7
B) 7 : 5
C) 3 : 6
D) 6 : 3
Correct Answer: B
Solution :
\[{{S}_{{{3}^{rd}}}}=10+\frac{10}{2}(2\times 3-1)=35\ m\] \[{{S}_{{{2}^{nd}}}}=10+\frac{10}{2}(2\times 2-1)=25m\] Þ \[\frac{{{S}_{{{3}^{rd}}}}}{{{S}_{{{2}^{nd}}}}}=\frac{7}{5}\]You need to login to perform this action.
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