A) 1:2
B) \[1:\sqrt{3}\]
C) \[\sqrt{3}:1\]
D) 1:3
Correct Answer: D
Solution :
The line making greater slope has greater velocity. Hence line making \[{{60}^{o}}\] has greater velocity. \[\therefore \] \[\frac{{{v}_{A}}}{{{v}_{B}}}=\frac{\tan {{30}^{o}}}{\tan {{60}^{o}}}=\frac{1\sqrt{3}}{\sqrt{3}}=\frac{1}{3}\]You need to login to perform this action.
You will be redirected in
3 sec