9th Class Science Time and Motion Question Bank Motion

  • question_answer
    Direction: Read the passage carefully and answer the following questions. A dancer is demonstrating dance steps along a straight line. The position-time graph of the dancer is given here.
     
    The average velocity of the dancer during time interval between t = 2 s to t = 9 s is

    A) \[1\text{ }m\text{ }{{s}^{-1}}\]

    B) \[-\text{ }0.57\text{ }m\text{ }{{s}^{-1}}\]

    C) \[2.75\text{ }m\text{ }{{s}^{-1}}\]

    D) \[-\text{ }0.29\text{ }m\text{ }{{s}^{-1}}\]

    Correct Answer: D

    Solution :

    During time interval t = 2 s to t = 9 s, six dance steps namely AB, BC, CD, DE, EF and FG have been demonstrated by the dancer. Total displacement \[=(0-2)=-2\text{ }m\] Total time taken \[=9-2=7s\] Average velocity\[=\frac{\text{total displacement}}{\text{total time taken}}\] Thus, average velocity\[=\frac{-2}{7}=-0.29m\text{ }{{\text{s}}^{-1}}\]


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