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JEE Main & Advanced Physics Electro Magnetic Induction Question Bank Motional EMI

  • question_answer
    A conductor of 3 m in length is moving perpendicularly to magnetic field of \[{{10}^{-3}}\]tesla with the speed of \[{{10}^{2}}m/s\], then the e.m.f. produced across the ends of conductor will be                                                             [MP PET 1990]

    A)             0.03 volt                                

    B)            0.3 volt

    C)            \[3\times {{10}^{-3}}volt\]     

    D)            3 volt

    Correct Answer: B

    Solution :

               \[e=Bvl=3\times {{10}^{-3}}\times {{10}^{2}}=0.3\ volt\]


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