A) 7
B) 6
C) 3
D) 0
Correct Answer: A
Solution :
We know that n! terminates in 0 for n ³ 5 and \[{{3}^{4n}}\] terminator in 1, (\[\because \]\[{{3}^{4}}=81)\] \[\therefore {{3}^{180}}={{({{3}^{4}})}^{45}}\] terminates in 1 Also \[{{3}^{3}}\] = 27 terminates in 7 \ \[{{3}^{183}}={{3}^{180}}{{3}^{3}}\] terminates in 7. \ \[183!+{{3}^{183}}\] terminates in 7 i.e. the digit in the unit place = 7.
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