A) \[n+1\]
B) \[n+3\]
C) \[\frac{(n+1)(n+2)}{2}\]
D) None of these
Correct Answer: C
Solution :
By converse rule, put n= 1, 2, then number of terms are 3, 6. Hence number of terms of (a+b+c)n \[=\frac{(n+1)(n+2)}{2}\].
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