| \[\mathbf{163}\times \mathbf{38}=(\mathbf{160}+\mathbf{3})\times \,\,[\,\,\,\,\,\,]\] |
A) \[\text{35}-\text{3}\]
B) \[\text{3}0+\text{3}\]
C) \[\text{35}+\text{3}\]
D) \[~\text{3}0+\text{5}\]
Correct Answer: C
Solution :
163 = 160 + 3 and 38 = 35 + 3 So, \[\text{163}\times \text{38}=(\text{16}0+\text{3})\times (\text{35}+\text{3})\] \[\therefore \] The missing number is \[(\text{35}+\text{3})\].
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