A) 4
B) 1
C) 8
D) 0.5
Correct Answer: D
Solution :
Mol. weight of \[CO=12+16=28\] \[(CO)x=(28)x\] Mol. weight of\[(CO)x=70\times 2=140\] \[\Rightarrow \] \[(28)x=140\] \[\therefore \] \[x=\frac{140}{28}=5\]You need to login to perform this action.
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