A) decreases
B) does not change
C) becomes zero
D) increases
Correct Answer: D
Solution :
[d] Key Idea: Charge remains constant after charging. |
If the battery is removed after charging then the charge stored in the capacitor remains constant. |
\[q=\]constant |
Change in capacitance |
\[C'=\frac{{{\varepsilon }_{0}}\,A}{d'}\] |
As \[d'>d\] |
hence, \[C'<C\] |
Hence, potential difference between the plates |
or \[V'\,\,\propto \,\,\frac{1}{C'}\] |
As capacitance decreases, so potential difference increases. |
Note: If the battery remains connected, the charge stores increases. Also the potential difference V becomes constant. |
You need to login to perform this action.
You will be redirected in
3 sec