NEET Physics Electrostatics & Capacitance Question Bank NEET PYQ - Electrostatics and Capacitance

A capacitor of capacity \[{{C}_{1}}\] is charged upto potential V volt and then connected in parallel to an uncharged capacitor of capacity \[{{C}_{2}}\]. The final potential difference across each capacitor will be: [AIPMT 2002]

A) \[\frac{{{C}_{2}}V}{{{C}_{1}}+{{C}_{2}}}\]

B) \[\frac{{{C}_{1}}V}{{{C}_{1}}+{{C}_{2}}}\]

C) \[\left( 1+\frac{{{C}_{2}}}{{{C}_{1}}} \right)V\]

D) \[\left( 1-\frac{{{C}_{2}}}{{{C}_{1}}} \right)V\]

Correct Answer: B

Solution :

[b] The common potential difference across two capacitors connected in parallel

\[V'=\frac{{{C}_{1}}{{V}_{1}}+{{C}_{2}}{{V}_{2}}}{{{C}_{1}}+{{C}_{2}}}\]

Here, \[{{V}_{1}}=V,\,\,\,{{V}_{2}}=0\]

\[\therefore \] \[V'=\frac{{{C}_{1}}V}{{{C}_{1}}+{{C}_{2}}}\]