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NEET Physics Electrostatics & Capacitance Question Bank NEET PYQ - Electrostatics and Capacitance

  • question_answer
    A parallel plate condenser has a uniform electric field E(V/m) in the space between the plates. If the distance between the plates is d(m) and area of each plate is \[A({{m}^{2}})\] the energy (joule) stored in the condenser is [AIPMT (S) 2011]

    A) \[\frac{1}{2}{{\varepsilon }_{0}}{{E}^{2}}\]

    B) \[{{\varepsilon }_{0}}EAd\]

    C) \[\frac{1}{2}{{\varepsilon }_{0}}{{E}^{2}}Ad\]

    D) \[{{E}^{2}}Ad/{{\varepsilon }_{0}}\]

    Correct Answer: C

    Solution :

    [c] The energy stored in the condenser
    \[U=\frac{1}{2}C{{V}^{2}}\]
    \[U=\frac{1}{2}\left( \frac{A{{\varepsilon }_{0}}}{d} \right){{(Ed)}^{2}}\left( \because C=\frac{A{{\varepsilon }_{0}}}{d}and\,V=Ed \right)\]
                \[U=\frac{1}{2}{{\varepsilon }_{0}}{{E}^{2}}Ad\]


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