NEET Physics Electrostatics & Capacitance Question Bank NEET PYQ - Electrostatics and Capacitance

  • question_answer
    A parallel plate condenser with oil (dielectric constant 2) between the plates has capacitance C. If oil is removed, the capacitance of capacitor becomes:                             [AIPMT 1999]

    A)  \[\sqrt{2}\,C\]

    B) 2 C

    C) \[\frac{C}{\sqrt{2}}\]

    D) \[\frac{C}{2}\]

    Correct Answer: D

    Solution :

    [d] The capacitance of a parallel plate capacitor with dielectric (oil) between its plates is.
                            \[C=\frac{K{{\varepsilon }_{0}}A}{d}\]  ...(i)
                where    \[{{\varepsilon }_{0}}=\] electric permittivity of free space
                            K = dielectric constant
                            A = area of each plate of capacitor
                            d = distance between two plates
                When dielectric (oil) is removed, so capacitance
                            \[{{C}_{0}}=\frac{{{\varepsilon }_{0}}A}{d}\]  …(ii)
                Comparing Eqs. (i) and (ii), we get
                            \[C=K{{C}_{0}}\]
    \[\Rightarrow \]   \[{{C}_{0}}=\frac{C}{K}=\frac{C}{2}(K=2)\]


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