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NEET Physics Electrostatics & Capacitance Question Bank NEET PYQ - Electrostatics and Capacitance

  • question_answer
    A short electric dipole has a dipole moment of \[16\times {{10}^{9\text{ }}}C\text{ }m\]. The electric potential due to the dipole at a point at a distance of 0.6 m from the centre of the dipole, situated on a line making an angle of \[60{}^\circ \] with the dipole axis is: \[\left( \frac{1}{4\pi {{\in }_{0}}}=9\times {{10}^{9}}N\,{{m}^{2}}/{{C}^{2}} \right)\]          [NEET 2020]

    A) 200 V

    B) 400 V

    C) zero

    D) 50 V

    Correct Answer: A

    Solution :

    [a] \[V=\frac{kp\,\cos \,\theta }{{{r}^{2}}}\]
                \[V=\frac{9\times {{10}^{9}}\times 16\times {{10}^{-9}}\times \cos \,60}{0.36}\]
                \[V=200\,V\]


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