A) Phosphine
B) Phosphoric acid
C) Phosphorus acid
D) No reaction
Correct Answer: A
Solution :
\[{{P}_{4}}+3{{H}_{2}}O+3NaOH\,\to \]\[\underset{\text{Phosphine}}{\mathop{P{{H}_{3}}}}\,\,\,+\underset{\text{Sod}\text{. hypophosphite}}{\mathop{3Na{{H}_{2}}P{{O}_{2}}}}\,\]
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