A) Urea
B) Potassium nitrate
C) Ammonium sulphate
D) Superphosphate of lime
Correct Answer: C
Solution :
\[{{(N{{H}_{4}})}_{2}}S{{O}_{4}}\] is a salt of weak base & strong acid \[{{(N{{H}_{4}})}_{2}}S{{O}_{4}}+2{{H}_{2}}O\,\to \,\underset{\text{Weak base}}{\mathop{2N{{H}_{4}}OH}}\,+\underset{\text{Strong acid}}{\mathop{{{H}_{2}}S{{O}_{4}}}}\,\]
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