A) \[NO\]
B) \[N{{H}_{4}}Cl\]
C) \[{{N}_{2}}{{H}_{4}}\]
D) \[HN{{O}_{2}}\]
Correct Answer: B
Solution :
\[3N{{H}_{3}}+OC{{l}^{-}}\,\to \,N{{H}_{2}}-N{{H}_{2}}+N{{H}_{4}}Cl+O{{H}^{-}}\]
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