A) \[N{{H}_{4}}OH\]
B) \[C{{a}_{3}}{{N}_{2}}\]
C) \[N{{H}_{4}}N{{O}_{2}}\]
D) \[Ba{{(N{{O}_{3}})}_{2}}\]
Correct Answer: C
Solution :
\[N{{H}_{4}}N{{O}_{2}}\,\to \,{{N}_{2}}+2{{H}_{2}}O\]
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