A) \[\sqrt{2}\,\,m/s\]
B) \[\sqrt{9.8}\,\,m/s\]
C) 4.43 m/s
D) \[1/\sqrt{2}\,\,m/s\]
Correct Answer: C
Solution :
\[v=\sqrt{2gl(1-\cos \theta )}=\sqrt{2\times 9.8\times 2(1-\cos 60{}^\circ )}\] \[=4.43\,m/s\]You need to login to perform this action.
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