A) \[x\]
B) \[x-y\]
C) 1
D) 0
Correct Answer: C
Solution :
(c): \[\frac{1}{1+{{2}^{x-y}}}+\frac{1}{1+{{2}^{y-x}}}\Rightarrow \frac{1}{1+\frac{{{2}^{x}}}{{{2}^{y}}}}+\frac{1}{1+\frac{{{2}^{y}}}{{{2}^{x}}}}\] \[\Rightarrow \frac{{{2}^{y}}}{{{2}^{y}}+{{2}^{x}}}+\frac{{{2}^{x}}}{{{2}^{y}}+{{2}^{y}}}=\frac{{{2}^{x}}+{{2}^{y}}}{{{2}^{x}}+{{2}^{y}}}=1\]You need to login to perform this action.
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