question_answer

The smallest number which when divided by 20, 25, 35 and 40 and leaves a remainder of 14, 19, 29 and 34, respectively is

A) 1394            

B) 1404

C) 1664                           

D) 1406

Correct Answer: A

Solution :

\[\sqrt{2},\sqrt{5},\sqrt{6},2\sqrt{3},5\sqrt{7},\sqrt{2}+\sqrt{3},\]  L.C.M. \[\sqrt[3]{2},\sqrt[3]{3},\sqrt[3]{4},\] \[2+\sqrt{3}\] \[\pi \] required number =\[\frac{22}{7}\]