JEE Main & Advanced
Mathematics
Three Dimensional Geometry
Question Bank
Numerical Value Type Questions - 3-Dimensional Geometry
question_answer
If the shortest distance between the line \[\frac{x-3}{3}=\frac{y-8}{-1}=\frac{z-3}{1}\] and \[\frac{x+3}{-3}=\frac{y+7}{2}=\frac{z-6}{4}\] is \[k\sqrt{30}\] then find k.