JEE Main & Advanced Mathematics Differential Equations Question Bank Numerical Value Type Questions - Differential Equation

  • question_answer The solution of \[\frac{dy}{dx}+\frac{y}{\left( 1+{{x}^{2}} \right)}=\frac{{{e}^{{{\tan }^{-1}}}}}{1={{x}^{2}}}\] is \[{{e}^{k\,{{\tan }^{-1}}x}}+2c\] then find k. 

    Answer:

    2.00


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