JEE Main & Advanced Mathematics Differential Equations 298 Question Bank Numerical Value Type Questions - Differential Equation

  • question_answer The solution of \[\frac{dy}{dx}=\frac{6{{x}^{2}}}{\left( 2y+\cos y \right)},y\left( 1 \right)=0,\] is \[{{y}^{2}}+\sin y=k{{x}^{3}}-2\] then find k.     

    Answer:

    2.00


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