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JEE Main & Advanced Mathematics Conic Sections Question Bank Numerical Value Type Questions - Hyperbola

  • question_answer
    If the foci of the ellipse \[\frac{{{x}^{2}}}{25}+\frac{{{y}^{2}}}{{{b}^{2}}}=1\] and the hyperbola \[\frac{{{x}^{2}}}{144}-\frac{{{y}^{2}}}{81}=\frac{1}{25}\] coincide, then find the value \[{{b}^{2}}.\]

    Answer:

    16.00


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