A) 0.5
B) 0.44
C) 0.6
D) None of these
Correct Answer: B
Solution :
Here \[P(X)=0.3;\] \[P(Y)=0.2\] Now \[P(X\cup Y)=P(X)+P(Y)-P(X\cap Y)\] Since these are independent events, so \[P(X\cap Y)=P(X)\,.\,P(Y)\] Thus required probability \[=0.3+0.2-0.06=0.44\] .You need to login to perform this action.
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