A) \[\frac{v}{4n}\]
B) \[\frac{v}{2n}\]
C) \[\frac{2n}{v}\]
D) \[\frac{4n}{v}\]
Correct Answer: A
Solution :
For shortest length of pipe mode of vibration must be fundamental i.e., \[n=\frac{v}{4l}\]Þ \[l=\frac{v}{4n}.\]You need to login to perform this action.
You will be redirected in
3 sec