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JEE Main & Advanced Physics Wave Mechanics Question Bank Organ Pipe (Vibration of Air Column)

  • question_answer
    An open tube is in resonance with string (frequency of vibration of tube is n0). If tube is dipped in water so that 75% of length of tube is inside water, then the ratio of the frequency of tube to string now will be    [J & K CET 2005]

    A)            1    

    B)            2

    C)            \[\frac{2}{3}\]                      

    D)            \[\frac{3}{2}\]

    Correct Answer: B

    Solution :

                       For open tube, \[{{n}_{0}}=\frac{v}{2l}\] For closed tube length available for resonance is \[l'=l\times \frac{25}{100}=\frac{l}{4}\] \ Fundamental frequency of water filled tube \[\,n=\frac{v}{4l'}=\frac{v}{4\times (l/4)}=\frac{v}{l}=2{{n}_{0}}\]Þ \[\frac{n}{{{n}_{0}}}=2\]


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