A) Replacing the air in the tube by hydrogen gas
B) Increasing the length of the tube
C) Decreasing the length of the tube
D) Opening the closed end of the tube
Correct Answer: A
Solution :
Fundamental frequency of closed pipe \[n=\frac{v}{4l}\] where \[v=\sqrt{\frac{\gamma RT}{M}}\] Þ\[v\propto \frac{1}{\sqrt{M}}\] \[\because \] \[{{M}_{{{H}_{2}}}}<{{M}_{air}}\,\,\Rightarrow \,\,{{v}_{{{H}_{2}}}}>{{v}_{air}}\] Hence fundamental frequency with H2 will be more as compared to air. So option (a) is correct. Also \[n\propto \frac{1}{l}\], hence if l decreases n increases so option (c) is correct. It is well known that (n)Open = 2(n)Closed, hence option (d) is correct.
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