A) \[4\times \frac{330}{4}Hz\]
B) \[3\times \frac{330}{4}Hz\]
C) \[2\times \frac{330}{4}Hz\]
D) \[2\times \frac{4}{330}Hz\]
Correct Answer: B
Solution :
For closed pipe \[{{n}_{1}}=\frac{v}{4l}=\frac{330}{4}\]\[Hz\] Second note = \[3{{n}_{1}}=\frac{3\times 300}{4}\]\[Hz\].
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