A) \[AlC{{l}_{3}}\]
B) \[C{{N}^{-}}\]
C) \[N{{H}_{3}}\]
D) \[C{{H}_{3}}OH\]
Correct Answer: A
Solution :
\[AlC{{l}_{3}}\] is lewis acid i.e., electron deficient compound. So it is electrophile.
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