JEE Main & Advanced Chemistry Redox Reactions / रेडॉक्स अभिक्रियाएँ Question Bank Oxidation number and Oxidation state

  • question_answer
    The oxidation number of nickel in \[{{K}_{4}}[Ni{{(CN)}_{4}}]\] is [JIPMER 1999]

    A) - 2         

    B) - 1

    C) + 2         

    D) 0

    Correct Answer: D

    Solution :

    \[{{K}_{4}}[\overset{*}{\mathop{Ni}}\,{{(CN)}_{4}}]\]            \[4\times (+1)+x+4\times (-1)=0\]                                 \[+4+x-4=0\Rightarrow x=0\].


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