A) + 2
B) + 4
C) + 6
D) + 7
Correct Answer: C
Solution :
The chemical structure of \[{{H}_{2}}{{S}_{2}}{{O}_{8}}\] is as follows:- \[H-O-\underset{O}{\overset{O}{\mathop{\underset{||}{\overset{||}{\mathop{S}}}\,}}}\,-O-O-\underset{O}{\overset{O}{\mathop{\underset{||}{\overset{||}{\mathop{S}}}\,}}}\,-O-H\] So the oxidation number of S should be : \[\underset{(\text{for}\,\,H)}{\mathop{2\times (+1)}}\,+\underset{(\text{for}\,\,S)}{\mathop{2\times X}}\,+\underset{(\text{for}\,\,O)}{\mathop{6\times (-2)}}\,+\underset{(\text{for}\,\,O-O)}{\mathop{2\times (-1)}}\,=0\] or \[X=+6\].
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