A) \[S{{O}_{2}}\]
B) \[{{H}_{2}}S{{O}_{4}}\]
C) \[N{{a}_{2}}{{S}_{2}}{{O}_{3}}\]
D) \[N{{a}_{2}}{{S}_{4}}{{O}_{6}}\]
Correct Answer: B
Solution :
\[\overset{*\,\,\,\,\,\,\,}{\mathop{S{{O}_{2}}}}\,=+4\] \[\overset{*}{\mathop{{{H}_{2}}S{{O}_{4}}}}\,=+6\] \[\overset{\,\,*}{\mathop{N{{a}_{2}}{{S}_{2}}{{O}_{3}}}}\,=+2\] \[\overset{\,\,*}{\mathop{N{{a}_{2}}{{S}_{4}}{{O}_{6}}}}\,=+\frac{5}{2}\].
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