A) \[HCHO\]
B) \[CHC{{l}_{3}}\]
C) \[C{{H}_{3}}OH\]
D) \[{{C}_{12}}{{H}_{22}}{{O}_{11}}\]
Correct Answer: B
Solution :
Oxidation number of C in \[HCHO=0\] \[CHC{{l}_{3}}=+2\] \[C{{H}_{3}}OH=-2\] \[{{C}_{12}}{{H}_{22}}{{O}_{11}}=0\]
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