JEE Main & Advanced Chemistry Redox Reactions / रेडॉक्स अभिक्रियाएँ Question Bank Oxidation number and Oxidation state

  • question_answer
    When \[S{{O}_{2}}\] is passed through acidic solution of potassium dichromate, then chromium sulphate is formed. Change in valency of chromium is             [CPMT 1979]

    A)                 +4 to +2               

    B)                 +5 to +3

    C)                 +6 to +3               

    D)                 +7 to +2

    Correct Answer: C

    Solution :

               \[\overset{+6}{\mathop{{{K}_{2}}C{{r}_{2}}{{O}_{7}}}}\,+3S{{O}_{2}}+{{H}_{2}}S{{O}_{4}}\to \]  \[{{K}_{2}}S{{O}_{4}}+\overset{\,\,\,\,\,+3\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}{\mathop{C{{r}_{2}}{{(S{{O}_{4}})}_{3}}}}\,+{{H}_{2}}O\]                 In this reaction chromium change from + 6 to +3 oxidation state.


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