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JEE Main & Advanced Chemistry Redox Reactions / रेडॉक्स अभिक्रियाएँ Question Bank Oxidation number and Oxidation state

  • question_answer
    The oxidation number of \[Cr\] in \[{{K}_{2}}C{{r}_{2}}{{O}_{7}}\]is [CPMT 1981, 85, 90, 93, 99; KCET 1992; BHU 1988, 98; AFMC 1991, 99; EAMCET 1986; MP PMT 1996, 99, 2002; MP PET/PMT 1998; Bihar CEE 1995; RPET 2000]

    A) +6          

    B) - 7

    C) +2          

    D) - 2

    Correct Answer: A

    Solution :

    \[\overset{*\,\,}{\mathop{{{K}_{2}}C{{r}_{2}}{{O}_{7}}}}\,\]           \[2+2x-2\times 7=0\]; \[2x-14+2=0\]                 \[2x=12\];  \[x=\frac{12}{2}=+6\].


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