A) 1
B) 3
C) 5
D) 6
Correct Answer: B
Solution :
\[{{[\overset{*\,\,}{\mathop{Cr}}\,{{({{H}_{2}}O)}_{4}}C{{l}_{2}}]}^{+}}\] \[x+0+2\,(-1)=+\,1\]; \[x-2=+\,1\] \[x=+\,3\] for Cr in complex.
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