A) 7 to 4
B) 6 to 4
C) 7 to 2
D) 4 to 2
Correct Answer: C
Solution :
\[5\underset{COOH}{\overset{COOH}{\mathop{|\,\,\,\,\,\,\,\,\,\,}}}\,+\overset{+7}{\mathop{2KMn{{O}_{4}}}}\,+3{{H}_{2}}S{{O}_{4}}\to \] \[{{K}_{2}}S{{O}_{4}}+\overset{+2\,\,\,\,\,\,\,\,\,}{\mathop{2MnS{{O}_{4}}}}\,+10C{{O}_{2}}+8{{H}_{2}}O\] In this reaction oxidation state of \[Mn\] change from + 7 to + 2.
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